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1. 甲醛被捕获

不需要酶 四氢叶酸(THF) + 甲醛(formaldehyde) - N5,N10-亚甲基四氢叶酸(5,10-methylene-THF) $化学方程式:$ - tikz \usepackage chemfig \begin document \chemfig THF + \chemfig CH 2O \begin tikzpicture

描述

不需要酶

[[四氢叶酸(THF)]]+[[甲醛(formaldehyde)]]->[[N5,N10-亚甲基四氢叶酸(5,10-methylene-THF)]]

$化学方程式:$

-

\usepackage{chemfig}
\begin{document}

\chemfig{
	THF
}

+
\chemfig{
CH_2O
}

\begin{tikzpicture} 
\draw [->] (0,0) to node[above] {} (1,0); 
\end{tikzpicture}

$
CH_2=FH_4
$
+$

\end{document}

-

\usepackage{chemfig}
\begin{document}

\chemfig{
	N(-[4,0.3]H)-[7,0.8](-[6,0.6]NH_2)=[,0.8]N-[1,0.8](=[,0.6]O)-[3,0.8]
	(-[1,0.8]N(-[,0.3]H)(-[4,0.3]5)-[3,0.8]
		(-[2,0.6]CH_2-[2,0.6]
			NH(-[4,0.3]10)-[2,0.6]**6(
			-
			-
			-(-[,0.6]C
				(=[4,0.7]O)
				(-[2,0.7]
					NH-[2,0.6]CH
						(-[4,0.6]HOOC)
						(-[2,0.6]CH_2
							(-[2,0.6]CH_2
								(-[2,0.6]COOH)
							)
						)
				)
			)
			-
			-
			-
		)
	)
	-[4,0.8]-[5,0.8]N(-[4,0.3]H)-[7,0.8])
	=[4,0.8]-[5,0.6]
}
+
\chemfig{
	(=[2,0.5]O)
	(-[4.5,0.5]H)
	(-[7.5,0.5]H)
} 
\begin{tikzpicture} 
\draw [->] (0,0) to node[above] {} (1,0); 
\end{tikzpicture}

\chemfig{
	N(-[4,0.3]H)-[7,0.8](-[6,0.6]NH_2)=[,0.8]N-[1,0.8](=[,0.6]O)-[3,0.8]
	(-[1,0.8]N(-[1.4,1])(-[4,0.3]5)-[3,0.8]
		(-[2,0.6]CH_2-[2,0.6]
			N(-[4,0.3]10)(-[7.3,1.3]CH_2)(-[4,0.3]10)-[2,0.6]**6(
			-
			-
			-(-[,0.6]C
				(=[4,0.7]O)
				(-[2,0.7]
					NH-[2,0.6]CH
						(-[4,0.6]HOOC)
						(-[2,0.6]CH_2
							(-[2,0.6]CH_2
								(-[2,0.6]COOH)
							)
						)
				)
			)
			-
			-
			-
		)
	)
	-[4,0.8]-[5,0.8]N(-[4,0.3]H)-[7,0.8])
	=[4,0.8]-[5,0.6]
}
+$

\end{document}