[[脱氢丙氨酸]]->[[C3:丙酮酸(pyruvate)]]+{3}$
$化学方程式:$
-
\usepackage{chemfig}
\begin{document}
\chemfig{
(-[0.7,1]COOH)
(<[6,0.8]NH_2)
(=[3.3,1])
}
\begin{tikzpicture}
\draw [->] (0,0) to node[above] {} (2,0); % 水平箭头
\end{tikzpicture}
\chemfig{
(=[5,0.8]O)
(-[3,0.8]HO)
(-[,0.5]
(=[1,0.8]O)
(-[7,0.8])
)
}
+
{3}$
\end{document}