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0. A:腺嘌呤(adenine)

腺嘌呤 adenine A smiles C1=NC2=NC=NC =C2N1 N $结构式:$ - IUPAC tikz \usepackage chemfig \begin document \chemfig - 4,,,,transparent 6 -N - ,0.3,,,transparent 3 - - ,0.3,,,trans

称谓

腺嘌呤 adenine A

3D结构

C1=NC2=NC=NC(=C2N1)N

描述

$结构式:$

• IUPAC

\usepackage{chemfig}
\begin{document}
\chemfig{
(-[4,,,,transparent])**6(
		-N(-[,0.3,,,transparent]3)
		-(-[,0.3,,,transparent]2)
		-N(-[,0.3,,,transparent]1)
		-(-[2.5,0.3,,,transparent]6)(-NH_2)
		-(-[1.5,0.3,,,transparent]5)**5(
			-N(-[,0.3,,,transparent]7)
			-(-[,0.3,,,transparent]8)
			-N(-[,0.3,,,transparent]9)
			-(-[5,0.3,,,transparent]4)
			-
		)
		-
	)
} 
\end{document}

-

\usepackage{chemfig}
\begin{document}
\chemfig[atom sep=2em,cram width=2pt]{
	(-[6,0.2,,,,transparent]H)(-[2,0.2,,,,transparent]
		N*5(-(
			*6(-N=-N=(-[2.4,,,1]NH_2)-=)
		)--N=-)
	)
}
\end{document}

^1

-

\usepackage{chemfig}
\begin{document}
\chemfig[atom sep=2em,cram width=2pt]{
	(-[6,0.2]H)(-[2,0.2]N
		*5(-(
			*6(-N=-N=(-[2.4,,,1]NH_2)-=)
		)--N=-)
	)
}
\end{document}

-

\usepackage{chemfig}
\begin{document}
\chemfig{
(=[6,0.5]-[7.5,0.5]N=[0.5,0.5]-[2,0.5]N=[3.5,0.5](-[2,0.5]NH_2)-[4.5,0.5])
(-[3.5,0.5]N=[5,0.6]-[7,0.5]N(-[6,0.3]H)-[0.25,0.5])
} 
\end{document}

-

\usepackage{chemfig}
\begin{document}
\chemfig{
N(-[6,0.3]H)
-[0.25,0.5]
	(-[7.5,0.5]N=[0.5,0.5]-[2,0.5]N=[3.5,0.5](-[2,0.5]NH_2)-[4.5,0.5]
	(-[3.5,0.5]N=[5,0.6]-[7,0.3])
	=[6,0.5])
}
\end{document}

形成的核苷酸

-

\usepackage{chemfig}
\begin{document}
\chemfig{
(-[4,,,,transparent])**6(
		-N(-[,0.3,,,transparent]3)
		-(-[,0.3,,,transparent]2)
		-N(-[,0.3,,,transparent]1)
		-(-[2.5,0.3,,,transparent]6)(-NH_2)
		-(-[1.5,0.3,,,transparent]5)**5(
			-N(-[,0.3,,,transparent]7)
			-(-[,0.3,,,transparent]8)
			-N(-[3.5,0.3,,,transparent]9)(-sugar)
			-(-[5,0.3,,,transparent]4)
			-
		)
		-
	)
} 
\end{document}

-

\usepackage{chemfig}
\begin{document}
\chemfig{
(-[4,,,,transparent])*6(
		-N(-[,0.3,,,transparent]3)
		=(-[,0.3,,,transparent]2)
		-N(-[1,0.3,,,transparent]1)
		=(-[2.5,0.3,,,transparent]6)(-N(-[0,]H)(-[2.7]H))
		-(-[1.5,0.3,,,transparent]5)*5(
			-N(-[,0.3,,,transparent]7)
			=(-[,0.3,,,transparent]8)
			-N(-[3.5,0.3,,,transparent]9)(-sugar)
			-(-[5,0.3,,,transparent]4)
			-
		)
		=
	)
} 
\end{document}