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C2的形成:转甲酰基酶(ATIC(E1))

5-氨基咪唑-4-氨甲酰核苷酸(AICAR) + N10-甲酰四氢叶酸(10-formyl-THF) - 5-甲酰胺基咪唑-4-氨甲酰核苷酸(FAICAR) + 四氢叶酸(THF) - B站版本: tikz \usepackage chemfig \begin document \chemfig \fbox R - 2,0.8 N - 2,0.25 9

[[5-氨基咪唑-4-氨甲酰核苷酸(AICAR)]]+[[N10-甲酰四氢叶酸(10-formyl-THF)]]->[[5-甲酰胺基咪唑-4-氨甲酰核苷酸(FAICAR)]]+[[四氢叶酸(THF)]]

• B站版本:

\usepackage{chemfig}
\begin{document}

\chemfig{
	\fbox{R}-[2,0.8]N(-[2,0.25]9)
	-[3.5,0.6](-[3.3,0.25]4)(-[4.5,0.7]N(-[2,0.25]3)(-[4,0.3]H_2))
	=[2,0.8](-[4.8,0.25]5)(-[3,0.7](=[2,0.7]O)
	(
		-[4.7,0.8]N(-[2,0.3]1)
		-[4,0.3]H_2
	)
	(-[6,0.25]6))
	-[0.5,0.8]N(-[5.5,0.25]7)(-[,0.3]H)
	=[6.55,0.8]
		(-[4,0.2]8)
		-[5.25,0.6]
}
+^{10}-CHO-FH_4$

\begin{tikzpicture} 
\draw [->] (0,0) to node[above] {ATIC(E1)} (1,0); 
\end{tikzpicture}

\chemfig{
	\fbox{R}-[2,0.8]N(-[2,0.25]9)
	-[3.5,0.6](-[3.3,0.25]4)(-[4.5,0.7]N(-[2,0.25]3)=[3.3,0.6](-[5,0.25]2))
	=[2,0.8](-[4.8,0.25]5)(-[3,0.7](=[2,0.7]O)
	(
		-[4.7,0.8]N(-[2,0.3]1)
		-[4,0.3]H_2
	)
	(-[6,0.25]6))
	-[0.5,0.8]N(-[5.5,0.25]7)(-[,0.3]H)
	=[6.55,0.8]
		(-[4,0.2]8)
		-[5.25,0.6]
}
+
$

\end{document}