6-磷酸葡萄糖酸脱氢酶（6PGD）

它能通过[[0. 磷酸戊糖途径（HMP途径，PPP途径）]]生成**NADPH**这一关键还原力

催化反应

[[C6：6-磷酸-葡萄糖酸（6-Phosphogluconic acid）]]+^+$-->[[C5：核酮糖-5-磷酸（ribulose 5-phosphate，Ru5P，RuMP）]]+NADPH+^+$+$

$化学方程式：$

\usepackage{chemfig}
\begin{document}

\chemfig{
	(-[3.5,0.8]HO)
	(=[6,0.8]O)
	(-[0.5,0.5]
		(<:[2,0.8]OH)
		(-[7.5,0.5]
			(<:[6,0.8]OH)
			(-[0.5,0.5]
				(<:[2,0.8]OH)
				(-[7.5,0.5]
					(<[6,0.8]OH)
					(-[0.5,0.5]-[7.5,0.8]\fbox{P})
				)
			)
		)
	)
}
+^+$

\begin{tikzpicture} 
\draw [->] (0,0) to node[above] {6PGD} (1,0); 
\end{tikzpicture}

\chemfig{
	(-[6,0.5]OH)
	(-[0.5,0.5]
		(=[2,0.5]O)
		(-[7.5,0.5]
			(<[6,0.8]OH)
			(-[0.5,0.5]
				(<:[2,0.8]OH)
				(-[7.5,0.5]
					(-[0.5,0.8]\fbox{P})
				)
			)
		)
	)
}

+NADPH+^+$+$

\end{document}